You are the packing-line engineer at the Riverbend Relief Depot. A storm hit the county, and the depot has to turn a warehouse full of loose supplies into identical family kits, get them on the right trucks, and pay for it all with $4,000.00. Factor it, pack it, schedule it, stack it, and cost it out.
This morning's delivery is on the dock: 84 water bottles, 126 granola bars, and 4,550 canned meals. Every family kit must be exactly the same, and nothing may be left over — that is the rule that makes this a factor problem.
A factor divides a number with nothing left over. A prime number has only two factors: 1 and itself (2, 3, 5, 7, 11 …). Breaking a number into primes tells you every way it can be split into equal groups.
Español: Un factor divide un número sin dejar residuo. Un número primo solo tiene dos factores: 1 y él mismo. Separar un número en primos te dice todas las formas de hacer grupos iguales.Click a blue number to split it into two factors. Keep splitting until every branch is green — green means prime and cannot be split again.
Q1.1 — Finish both trees. What is the largest prime factor that 84 and 126 share?
Write both prime lists side by side. Circle the primes that show up in both lists. The biggest circled prime is the answer.
Español: Escribe las dos listas de primos. Encierra los primos que aparecen en las dos listas. El mayor de esos primos es la respuesta.Use the packer to try a number of kits. The depot needs the greatest number of identical kits with zero bottles and zero bars left over.
Q2.1 — What is the greatest number of identical kits?
Q2.2 — Water bottles in each kit?
Q2.3 — Granola bars in each kit?
GCF = greatest common factor. From Task 1, 84 = 2 × 2 × 3 × 7 and 126 = 2 × 3 × 3 × 7. Multiply the primes they share: 2 × 3 × 7.
Español: El MCD (máximo común divisor) es el producto de los primos que los dos números comparten: 2 × 3 × 7.Prove it without listing factors: any number of kits must divide both 84 and 126, so it can only be built from the primes both share. Why does that make 2 × 3 × 7 the largest possible?
Truck A returns every 6 days. Truck B returns every 8 days. Both were at the depot on Day 0. Click the buttons to mark each truck's days, then find the next day they meet.
Q3.1 — After Day 0, what is the next day both trucks are at the depot?
Q3.2 — The depot runs for 72 days. Not counting Day 0, how many times do both trucks arrive together?
LCM = least common multiple. Count by 6: 6, 12, 18, 24. Count by 8: 8, 16, 24. The first number in both lists is the LCM.
Español: El mcm (mínimo común múltiplo) es el primer número que aparece en las dos listas: cuenta de 6 en 6 y de 8 en 8.6 × 8 = 48, but the trucks meet on Day 24. Explain why multiplying the two cycles does not always give the LCM. (Hint: look at the prime factors they share.)
4,550 canned meals arrived. A shipping case holds exactly 24 cans. Use the stacker to fill cases, then answer what the depot supervisor needs to know.
Q4.1 — How many full cases can the depot ship?
Q4.2 — How many cans are left loose after the last full case?
The remainder is cans, not a decimal. You cannot ship 0.58 of a case. Multiply your case count by 24 and subtract from 4,550 to find what is left.
Español: El residuo son latas, no un decimal. Multiplica las cajas por 24 y resta de 4,550.Each full case costs $19.20. Pallet wrap for the whole order is a flat $5.20. The depot has $4,000.00. Fill in the cost board.
| Line item | Math | Amount |
|---|---|---|
| Full cases of canned meals | 189 cases × $19.20 | Q5.1 |
| Pallet wrap | flat charge | $5.20 |
| Money left from $4,000.00 | $4,000.00 − (cases + wrap) | Q5.2 |
Q5.1 — Cost of the 189 full cases at $19.20 each.
Q5.2 — Add the $5.20 wrap, then subtract from $4,000.00. How much is left?
Q5.3 — A case is $19.20 for 24 cans. What does one can cost?
Estimate first, then compute. $19.20 is about $19, and 189 is about 190, so the answer should land near $3,600. If your answer is $362 or $36,000, your decimal point moved.
Español: Primero estima. $19 × 190 ≈ $3,600. Si tu respuesta está muy lejos, el punto decimal está mal colocado.With the $366.00 left over, how many more full cases could the depot buy at $19.20 each — and how much would still be unspent?
The order slip lists 84 bottles + 126 bars. Rewrite it as one multiplication using the number of kits. Tap a factor to pull it out front.
84 + 126 = ? × ( ? + ? )
Q6.1 — Using the greatest common factor, complete: 84 + 126 = 42 × ( ___ )
Divide each part by 42: 84 ÷ 42 = 2 and 126 ÷ 42 = 3. Put those inside the parentheses and add them. Check it: 42 × 5 = 210, and 84 + 126 = 210.
Español: Divide cada parte entre 42: 84 ÷ 42 = 2 y 126 ÷ 42 = 3. Suma esos números dentro del paréntesis.When every depot check passes, submit your supply plan. Enter your name in the field below, then press Submit plan & grade to save your score as a PDF or DOC.
| Level | Score | Descriptor |
|---|---|---|
| 4 — Exceeds | 11–12 / 12 | Builds both prime factorizations and uses them to justify the GCF and LCM rather than guessing. Divides accurately, explains the remainder as cans, holds the decimal budget, and rewrites the sum with the distributive property. |
| 3 — Meets | 9–10 / 12 | Finds the GCF, the LCM, the case count, and the budget totals with at most one arithmetic slip. Distinguishes GCF from LCM correctly. |
| 2 — Approaching | 5–8 / 12 | Completes factor trees and simple division but confuses GCF with LCM, or reports the remainder as a decimal. Partial budget work. |
| 1 — Beginning | 0–4 / 12 | Few correct answers. Needs reteaching on prime factorization and on what "nothing left over" means. Re-run Tasks 1 and 2 with the Level 1 supports. |